$2\mathrm{.}11$ Position and Velocity of a Ball If a stationary ball is released at a height $h_0$ above the surface of the Earth with a vertical velocity $v_0,$ the position and velocity of the ball as a function of time will be given by the equations

$(2\mathrm{.}40)$

$h(t)=\frac{1}{2}g{t}^2+v_{0}t+h_0$