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2 10 pts Here is some data of a few patient's pulse measurement: Pulse (bpm) 70 46 86 70 64 76 88 Find the mean

2 10 pts Here is some data of a few patient's pulse measurement: Pulse (bpm) 70 46 86 70 64 76 88 Find the mean of a variable "pulse rate". Find the standard deviation of a variable "pulse rate" Use the correct symbol and choose the correct formula from the list. Plug in numbers, you don't have actually to calculate it. The correct answer is 14.2227bpm. What would be unusually high and unusually low pulse rate? {:( bar(x))=(1)/(n)sum_(i=1)^(n)x_(i),2)s=sqrt((sum(x_(i)-( bar(x)))^(2))/(n-1)),3)r=((x_(i)-( bar(x)))(y_(i)-( bar(y))))/(s_(x)s_(y))

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