2. [1/2 Points] DETAILS PREVIOUS ANSWERS Example 22.2 A Proton Moving Perpendicular to a Uniform Magnetic Field A proton is moving in a circular orbit of radius 13.9 cm in a uniform 0.328-T magnetic field perpendicular to the velocity of the proton. Find the speed of the proton. SOLVE IT Conceptualize From our discussion in this section, we know that the proton follows a circular path when moving in a uniform magnetic field. Categorize We evaluate the speed of the proton using an equation developed in this section, so we categorize this example as a substitution problem. Solve the equation for the speed of the particle: V= mp Substitute numerical values: V = - (1.60 x 10-19 C) (0.328 T) (0.139 m) 1.67 x 10-27 kg V = 4.37e06 m/s MASTER IT HINTS: GETTING STARTED | I'M STUCK! If an electron moves perpendicular to the same magnetic field with this same translational speed, what is the radius of its circular orbit? r = * m You may have interchanged the mass of the electron and the mass of the proton. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error