$22046$ Lb of mineral rock containing $60\%$ aluminum is processed to extract said metal.

First, the entire rock is placed in a storage yard, then it is

It is transported to the mill section, where it is ground to a powder consistency. Afterwards, said rock powder is mixed with $40$m of water in vats $($p$=0\mathrm{.}998$ g$/$cm$).$ In these vats, bubbling is activated through which all of the aluminum is separated, which has a moist consistency $(5\%$ of the current$).$

After this separation, the rock that remains at the bottom is transported to a dryer where $95\%$ of the water is removed. The rock is again used to fill abandoned mines.

On the other hand, wet aluminum is dried in an oven, completely removing the water. Once dry, $90\%$ of the aluminum is sent to the smelter while the rest is used to make Al$2($SO$4)=$ which is used in water treatment plants.

To create the sulfate, aluminum plus sodium hydroxide $(1$ ton$)$ is introduced into a reactor to produce the hydroxide $($n$=90\%).$

The hydroxide goes to a second reactor, mixing with sulfuric acid $(500$L$,$ p$=1\mathrm{.}02$ g$/$cm$)1543\mathrm{.}236$ Lb of water $($n$=95\%)$ where the desired product is obtained.

Perform the material balance to find the aluminum that is going to be smelted and that which is going to the first reactor.

How much aluminum sulfate is obtained from the second reactor?

Tip, handle all balance in tons.