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2 . 3 4 Determine the present worth of a geometric gradient series with a cash flow of $ 5 0 , 0 0 0

2.34 Determine the present worth of a geometric gradient series with a cash flow of $50,000 in year 1 and increases of 6% each year through year 8. The interest rate is 10% per year.
2.34Pg=50,0001-[1+0.061+0.10]80.10-0.06
=$320,573
2.35 Determine the difference in the present worth values of the following two commodity contracts at an interest rate of 8% per year. Contract 1 has a cost of $10,000 in year 1; costs will escalate at a rate of 4% per year for 10 years. Contract 2 has the same cost in year 1, but costs will escalate at 6% per year for 11 years.
2.35Pg1=10,0001-[1+0.041+0.08]100.08-0.04
=$78,590
Pg2=10,0001-[1+0.061+0.08]110.08-0.06
=$92,926
Difference =$14,336
3.3 The net cash flow associated with development and sale of a new product is shown. Determine the present worth at an interest rate of 12% per year. The cash flow is in $1000 units. Show ( a ) hand and ( b ) spreadsheet solutions.
]=[-120(PF,12%,1)-100(PF,12%,2)-40(PF,12%,3)+50(PA,12%,2)(PF,12%,3)
(b) Enter cash flows in, say, column A, and use the function =NPV(12%,A2:A10)**1000 to display $-71,308.
3.4 Standby power for water utility pumps and other electrical devices is provided by diesel-powered generators. As an alternative, the utility can use natural gas to power the generators, but it will be a few years before the gas is available at remote sites. The utility estimates that by switching to gas, it will save $22,000 per year, starting 3 years from now. At an interest rate of 8% per year, determine the present worth in year 0 of the projected savings that will occur in years 3 through 10.
]=[22,000(PA,8%,8)(PF,8%,2)
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