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( 2 5 p ) 1 = 1 6 * 1 0 - 6 1 C O 2 = 1 2 * 1 0 -

(25p)
1=16*10-61CO
2=12*10-61Co
E1=100GPa
E2=200GPa
allow1=100MPa
allow2=150MPa
In the figure, a circular cross-section rod with a diameter of 4cm, made of material with
number 1, is placed inside the pipe produced from material with number 2. The entire
system is mounted on a rigid plate from below and on a fixed wall from above. The
temperature when the system is installed is 10C. How much should the temperature be
changed to close the 0.023cm gap?
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