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2. [5 pts) There is an alternative relational algebra operator division (/). Consider two relation R and S whose schemas are (A1,.. ,Am,B1,...,Bn) and (B1,

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2. [5 pts) There is an alternative relational algebra operator division (/). Consider two relation R and S whose schemas are (A1,.. ,Am,B1,...,Bn) and (B1, .. ,Bn) respectively. R/S returns a relation of schema (A1,.. ,Am) where each record p is associated with all tuple s of S in R (i.e., you can always find (p,s) in R). (1) Use the relational algebra operator we discuss in class to express R/S. (2) Write a TRC query to express R/S. 2. [5 pts) There is an alternative relational algebra operator division (/). Consider two relation R and S whose schemas are (A1,.. ,Am,B1,...,Bn) and (B1, .. ,Bn) respectively. R/S returns a relation of schema (A1,.. ,Am) where each record p is associated with all tuple s of S in R (i.e., you can always find (p,s) in R). (1) Use the relational algebra operator we discuss in class to express R/S. (2) Write a TRC query to express R/S

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