2) A spring of constant k=1.2 N/cm is being compressed 5-cm by a 200-gram ball. The...

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2) A spring of constant k=1.2 N/cm is being compressed 5-cm by a 200-gram ball. The ball is released on a 10 degree incline. Determine: a) The speed of the ball when it leaves the spring b) The maximum height the ball will attain relative to the launch position 10 CompressED POSITION h =A Av v=dx dt = dv dt PHYSICS 105 EQUATION SHEET g= 9.8 m/sec/sec g= 32.2 ft/sec/sec total = + a = dv dt x=x+vt v=v+t (*-*)=t+1/2t v = v+2a(x-x) V+V v = 2 (x-x)=vt Wt-mg = ma JR HEFN f, ,FN f =FN f, SH,PN avg = AF Av tan=v/gr P = W/t = Fy 2 Work = [Fdr Work 1/2mv-1/2mv = K+U+U, = const K=1/2my U = mgy U-1/2kx TE=fd e(v)=(vv) m +mv mv, +mv W = mg 2) A spring of constant k=1.2 N/cm is being compressed 5-cm by a 200-gram ball. The ball is released on a 10 degree incline. Determine: a) The speed of the ball when it leaves the spring b) The maximum height the ball will attain relative to the launch position 10 CompressED POSITION h =A Av v=dx dt = dv dt PHYSICS 105 EQUATION SHEET g= 9.8 m/sec/sec g= 32.2 ft/sec/sec total = + a = dv dt x=x+vt v=v+t (*-*)=t+1/2t v = v+2a(x-x) V+V v = 2 (x-x)=vt Wt-mg = ma JR HEFN f, ,FN f =FN f, SH,PN avg = AF Av tan=v/gr P = W/t = Fy 2 Work = [Fdr Work 1/2mv-1/2mv = K+U+U, = const K=1/2my U = mgy U-1/2kx TE=fd e(v)=(vv) m +mv mv, +mv W = mg