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2} A uniform beam of mass 41/1 = 15!] kg and length L = Lil-m is let go from a horizontal position, swings from a.

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2} A uniform beam of mass 41/1 = 15!] kg and length L = Lil-m is let go from a horizontal position, swings from a. frictionless pivot at one end, and strikes a stationary block of mass m. = 35kg as shown. Assume that everything is frictionless and that collision is elastic. Furthermore, assume the size of the box and the 1width of the beam are negligible compared to the length of the beam. [a] ICalculate the angular speed of the beam. at. just before it strikes the block. {b} lGiven that the collision is elastic. kinetic energy and angular momentum will be conserved during the collision. Using this fact, calculate the speed of the block. us. immediately after the collision. Hint: calculate angular momenta of the beam and the block about the pivot point. using the sign mnvention where 5; points into the page and a! = 19' is positive for clockwise rotations

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