2. Consider the global NO formation reaction: N +0,2NO 2 d[NO] dt = k[N]"[O]" Along with a thermal mechanism: (Zeldovich) (1) O+N NO+N E = 315 kJ/mol (2) N+O NO+O E = 26 kJ/mol Forward reaction (1) is endothermic and due to the high E requires high temperatures (>1800K) to proceed and is very slow. From above two reactions, using basic arguments, derive the following expression for the "initial" NO reaction rate for the global reaction: d[NO] dt KP ref = = 2k [N][0]" fRT KG