(2) Determination of the density of an unknown liquid PROCEDURE: (a) Choose oil instead of water by clicking on the radio button. (b) 'Drop' the wooden block into the tank and then place the metal block on top of it. (c) Record the new volume of the oil. New volume = 110.89L (d) The scale reading with the two blocks on it = Wapparent = 0.03N (e) Subtract the initial volume of the oil without the blocks from the new volume. This is the volume of displaced water, AV = new volume - initial volume =_ L (n) Convert AV to m'. AV = m3 IL = 1000mL = 1000cm. 100cm = 1m (g) Find the total weight of the blocks. (h) Since Wtotal - Wapparent = AVDg according to Archimedes' Principle, find the density of the unknown oil by substituting the values into the following formula. (i) Calculate the experimental density of the oil. Dexp = Wtotal-Wapparent AVg kg/m' where g is the acceleration due to gravity, 9.8 m/s2. (j) Finally, calculate the percent difference by considering Dive = 918 kg/m'. Percent Difference = true -Dexy x 100% = %. [2 points]