2 erge & Center v V A. B C D E Probability 0.12 0.88 0.2 0.096 0.904 0 3 Given Probabilities: 4 P(inspected car has problems) 5 P(inspected car has no problems) 6 7 P(no problem found | inspected car has problems) P(problem found | inspected car has problems) 8 P(no problem found | inspected car has no problems) 9 P(problem found | inspected car has no problems) 10 11 1. The goal is to find P(inspected car has problems | no problem was found). 12 13 P(inspected car has problems | no problem was found) = 0.0265 14 P(inspected car has problems AND no problem found)/P(no problem found) = 0.0265 0.18 t 15 16 17 18 P(no problem found | inspected car has problems)*P(inspected car has problems)/ (P(no problem found | inspected car has problems)*P(inspected car has problems) + P(no problem found | inspected car has no problems)*P(inspected car has no problems)) which is equal to ... (results) 0.8099 19 20 2. Provide a brief clarification discussion about your results. 21 The probability that a car passes an inspection that has problems is 2.65% 22 The probability that a inspected car has problems and no problem is found among all the cars in which no problem is found is 18% 23 The probability of cars with problems that passed inspections divided by the probability of cars with problems that passed inspections 24 + the probability of cars with no problems that pass inspection*the probability of inspected cars with no problems is 80.99% 25 26 27 28 29 30 31 32 33 34 35 DADM_Tools 0 Define Name v Trace Use in Formula v Trace Function Sum Recently Financial Logical Used Text Date & Time Lookup & Math & Reference Trig More Functions Name Manager Create from Selection Remove J9 X fx 23 Given Probabilities: 4 P(inspected car has problems) 5 P(inspected car has no problems) 6 P(no problem found | inspected car has problems) 7 P(problem found | inspected car has problems) 8 P(no problem found | inspected car has no problems) 9 P(problem found | inspected car has no problems) 10 A 11 1. The goal is to find P(inspected car has problems | no problem was found). 12 13 P(inspected car has problems | no problem was found) = 14 P(inspected car has problems AND no problem found)/P(no problem found) = 15 16 P(no problem found | inspected car has problems) *P(inspected car has problems)/ 17 18 (P(no problem found | inspected car has problems)*P(inspected car has problems) + P(no problem found | inspected car has no problems)*P(inspected car has no problems)) 19 10 + B Probability 0.12 0.88 0.2 =1-88 =(B6*B4+1*B5) =(B4*B6/B8) =B11 =B6/(B6+B8) which is equal to ... (results) =B6*B4/B6*B4+B8*B5 20 2. Provide a brief clarification discussion about your results. 21 The probability that a car passes an inspection that has problems is 2.65% 22 The probability that a inspected car has problems and no problem is found among all the cars in which no problem is found is 18% 23 The probability of cars with problems that passed inspections divided by the probability of cars with problems that passed inspections 24+the probability of cars with no problems that pass inspection*the probability of inspected cars with no problems is 80.99% 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39