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(2) Find an inverse of 23 modulo 120 . Also solve 23x3(mod120) for x . (Hint: Use Euclid's Algorithm & Extended Euclid's

(2) Find an inverse of " 23" modulo " 120" ". Also solve 23x3(mod120) for " x ". (Hint: Use Euclid's Algorithm \& Extended Euclid's Algorithm) (3) Use the Fermat's little theorem to find: 352(mod 11)

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