2. Find the critical numbers of f(x) = v4-x2. (A) = -4,0,4 (B) =-4,4 (C) = -2,2 (D) x= -2,0,2 (E) There are no critical numbers4. If f(x) = xln(x-), then dy (A) In(x2) + 2 (B (C) (D) In(x-) + (E) 41(x) T5. The approximate area between the graph of y = - + 2 and the r-axis between r = 1 and c = 4, using 3 rectangles of equal width and the RIGHT- HAND endpoints, is: (A) 35 (B) 38 (C) 20 (D) 14 (E) 29\fdy 3r 16. The solution of the differential equation -, 1 0, with the initial 16. y condition y(0) = 1 is: 3r- + 1 (A) y = 307 (B) y = et (C) y = (D) y = + 1 (E) y = V3x- +1 2 2