Question
2: Gaseous dinitrogen pentoxide, above its sublimation point of 47C, can decompose into nitrogen dioxide and molecular oxygen. The data below were measured at 60C
2: Gaseous dinitrogen pentoxide, above its sublimation point of 47C, can decompose into nitrogen dioxide and molecular oxygen. The data below were measured at 60C in a closed container.
t (sec) | p(N2O5) (atm) | Ln{p(N2O5)} | 1/{p(N2O5)} |
0.0 | 0.250 | -1.386 | 4.00 |
60.0 | 0.213 | -1.546 | 4.695 |
120.0 | 0.182 | -1.704 | 5.495 |
180.0 | 0.156 | -1.858 | 6.410 |
240.0 | 0.133 | -2.017 | 7.519 |
300.0 | 0.113 | -2.180 | 8.850 |
2N2O5 4NO2 + O2
trend line appears to be more reliable and consistent with the first order
(c) Determine the rate constant (include appropriate units) for this reaction at 60.0 oC. (d) What is the half-life (sec) for this reaction if the initial pressure of N2O5(g) would be 0.400 atm? (e) Write the complete rate law for this reaction. (f) What is the rate (M/sec) of dinitrogen pentoxide at t = 2.00 min? Hint: Use the Ideal Gas Law. (g) What is the rate (M/sec) of nitrogen dioxide formation at t = 2.00 min? Hint: Use relative rates. (h) One of several Lewis structures for dinitrogen pentoxide is shown above dinitrogen pentoxide is a planar molecule stabilized by resonance. Given this Lewis structure of N2O5(g) written above, write out a plausible three-step mechanism that agrees with the correct rate law for this reaction. Write the rate law for each elementary step in your mechanism and identify the rate-determining step. (i) If the activation energy for this decomposition is 103.5 kJ/mol, at what temperature (C) will the rate constant for this reaction be twice as large as at 60.0 C (see your answer to part (c) and assume that the frequency factor for this reaction remains constant as temperature varies).
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