Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

2. Provide the MAC address of the network adapter which is the source of the traffic sent in the first packet of the file examined

image text in transcribed

2. Provide the MAC address of the network adapter which is the source of the traffic sent in the first packet of the file examined with Wireshark.

3. Provide the MAC address of the network adapter which is the destination of the traffic sent in the first packet of the file examined with Wireshark.

4. What are the first 6 bytes, listed as 12 hexadecimal characters, in the Packet Bytes pane for the first packet of the file examined with Wireshark; what do these characters represent?

can someone explain question number four for me ?

No. Time Source 1 2004/324 16:29:14. 159269 10.1.1.101 2 2004/324 16:29:14. 159920 10.1.1.1 3 2004/324 16:29:14. 159966 10.1.1.101 4 2004/324 16:29:14.172938 10.1.1.101 5 2004/324 16:29:14.173999 10.1.1.1 6 2004/324 16:29:14. 191558 10.1.1.1 7 2004/324 16:29:14.191615 10.1.1.1 8 2004/324 16:29:14. 191676 10.1.1.101 9 2004/324 16:29:14.281052 10.1.1.101 10 2004/324 16:29:14.295571 10.1.1.101 11 2004/324 16:29:14.296049 10.1.1.1 Destination 10.1.1.1 10.1.1.101 10.1.1.1 10.1.1.1 10.1.1.101 10.1.1.101 10.1.1.101 10.1.1.1 209.225.11.237 10.1.1.1 10.1.1.101 Protocol Length Info TCP 62 3177 + 80 [SYN] Seq=0 Win=0 Len=0 MSS=14 TCP 62 80 3177 [SYN, ACK] Seq=0 Ack=1 Win=584 TCP 54 3177 80 [ACK] Seq=1 Ack=1 Win=65535 Le HTTP 530 GET / HTTP/1.1 TCP 60 80 3177 [ACK] Seq=1 Ack=477 Win=6432 HTTP 489 HTTP/1.1 200 OK (text/html) TCP 60 80 3177 [FIN, ACK] Seq=436 Ack=477 Win TCP 54 3177 80 [ACK] Seq=477 Ack=437 Win=6510 TCP 62 3179 80 [SYN] Seq=0 Win=0 Len=0 MSS=14 TCP 54 3177 + 80 (FIN, ACK] Seq=477 Ack=437 Win TCP 60 80 3177 TACK1 Sea=437 Ack=478 Win=6432 > Frame 1: 62 bytes on wire (496 bits), 62 bytes captured (496 bits) Ethernet II, Src: SMCNetwo_22:52:03 (00:04:e2:22:5a:03), Dst: Kye_20:6c:df (00:c0:df:20:6c:df) > Destination: Kye_20:6c:df (00:c0:df:20:6c:df) Source: SMCNetwo_22:5a:03 (00:04:02:22:5a:03) Address: SMCNetwo_22:5a:03 (00:04:e2:22:5a:03) = LG bit: Globally unique address (factory default) = IG bit: Individual address (unicast) Type: IPv4 (0x0800) > Internet Protocol Version 4, Src: 10.1.1.101, Dst: 10.1.1.1 > Transmission Control Protocol, Src Port: 3177, Dst Port: 80, Seq: 0, Len: 0 1... 0000 0010 0020 0030 00 co df 20 6c df 00 04 20 30 b3 05 40 00 80 96 01 01 Oc 69 00 50 34 90 00 00 26 e5 00 00 02 04 e2 22 5a 03 08 00 45 00 31 5b Oa 01 01 65 Oa 01 04 7e 00 00 00 00 70 02 05 b4 01 01 04 02 . " ZE 1C p EN ...i.P4 & O http_with_jpegs(1).cap Packets: 483. Displayed: 483 (100.0%) Profile: DE No. Time Source 1 2004/324 16:29:14. 159269 10.1.1.101 2 2004/324 16:29:14. 159920 10.1.1.1 3 2004/324 16:29:14. 159966 10.1.1.101 4 2004/324 16:29:14.172938 10.1.1.101 5 2004/324 16:29:14.173999 10.1.1.1 6 2004/324 16:29:14. 191558 10.1.1.1 7 2004/324 16:29:14.191615 10.1.1.1 8 2004/324 16:29:14. 191676 10.1.1.101 9 2004/324 16:29:14.281052 10.1.1.101 10 2004/324 16:29:14.295571 10.1.1.101 11 2004/324 16:29:14.296049 10.1.1.1 Destination 10.1.1.1 10.1.1.101 10.1.1.1 10.1.1.1 10.1.1.101 10.1.1.101 10.1.1.101 10.1.1.1 209.225.11.237 10.1.1.1 10.1.1.101 Protocol Length Info TCP 62 3177 + 80 [SYN] Seq=0 Win=0 Len=0 MSS=14 TCP 62 80 3177 [SYN, ACK] Seq=0 Ack=1 Win=584 TCP 54 3177 80 [ACK] Seq=1 Ack=1 Win=65535 Le HTTP 530 GET / HTTP/1.1 TCP 60 80 3177 [ACK] Seq=1 Ack=477 Win=6432 HTTP 489 HTTP/1.1 200 OK (text/html) TCP 60 80 3177 [FIN, ACK] Seq=436 Ack=477 Win TCP 54 3177 80 [ACK] Seq=477 Ack=437 Win=6510 TCP 62 3179 80 [SYN] Seq=0 Win=0 Len=0 MSS=14 TCP 54 3177 + 80 (FIN, ACK] Seq=477 Ack=437 Win TCP 60 80 3177 TACK1 Sea=437 Ack=478 Win=6432 > Frame 1: 62 bytes on wire (496 bits), 62 bytes captured (496 bits) Ethernet II, Src: SMCNetwo_22:52:03 (00:04:e2:22:5a:03), Dst: Kye_20:6c:df (00:c0:df:20:6c:df) > Destination: Kye_20:6c:df (00:c0:df:20:6c:df) Source: SMCNetwo_22:5a:03 (00:04:02:22:5a:03) Address: SMCNetwo_22:5a:03 (00:04:e2:22:5a:03) = LG bit: Globally unique address (factory default) = IG bit: Individual address (unicast) Type: IPv4 (0x0800) > Internet Protocol Version 4, Src: 10.1.1.101, Dst: 10.1.1.1 > Transmission Control Protocol, Src Port: 3177, Dst Port: 80, Seq: 0, Len: 0 1... 0000 0010 0020 0030 00 co df 20 6c df 00 04 20 30 b3 05 40 00 80 96 01 01 Oc 69 00 50 34 90 00 00 26 e5 00 00 02 04 e2 22 5a 03 08 00 45 00 31 5b Oa 01 01 65 Oa 01 04 7e 00 00 00 00 70 02 05 b4 01 01 04 02 . " ZE 1C p EN ...i.P4 & O http_with_jpegs(1).cap Packets: 483. Displayed: 483 (100.0%) Profile: DE

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started