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2. We have argued in the lecture that if the table size is doubled when it's full, then the amortized cost per insert is acceptable.

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2. We have argued in the lecture that if the table size is doubled when it's full, then the amortized cost per insert is acceptable. Fred Hacker claims that this consumes too much space. He wants to try to increase the size with every insert by just two over the previous size. What is the amortized cost per insertion in Fred's table

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