2.16. Draw shear and moment diagrams for the beam analyzed in Question 2.7 [Figure 2.59(Q7)]. Answer: V = max -2000 lb and M max = -10,000 ft-lb. 28 [Figure R2 ent ent Principles of Mechanics 0 = 75 P60 1.5P the Ceel, Pa). a of (Q1) 1000 lb 2P 8 ft 12 ft. (Q5) w= 2 kips/ft W 5 105 (Q9) tively City of ased L12+ L/2+ (Q13a) poss load P (Q2) P 2000 lb (Q3) P45 P30 (Q6) 5ft 5 kips 15 ft (Q7) FL/3+2L/3 (Q10) +L/2+L12 (Q13b) 7 2P 0 = 45 7P (Q4) 4P 2P 1+1+1 (Q8) W = 2 kips W 4 ft 4 ft 12 ft (Q11) 0 = 45 (Q12) L L L +L/2+L/2. L12L12. (Q13c) (Q13d) FIGURE 2.59 Questions. EXAMPLE Find the elongation caused by a tensile force of 7500 lb (33,364 N) in a steel member 144 in. (3658 mm) long having a cross-sectional area of 0.785 in. (506.5 mm). Note that E=29.6 x 106 lb/in.2 (204,000 MPa).