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22. What is the result after the following code fragment executes? (8 pts) 5 3 AX= Ht ft DB Ht in DB ; code segment
22. What is the result after the following code fragment executes? (8 pts) 5 3 AX= Ht ft DB Ht in DB ; code segment MOV BL, 12 BX= MOV AL, ht_ft MUL BL CX= MOV DL, ht in DX = MOV DH, 00h ADD AX, DX 23. Consider the following program..... .DATA New word DW 1C5Fh .CODE Main PROC mov ax, si mov ax, 0005h add ax, new_word mov bx, 00ABh Main ENDP END Main Circle all of the problems from the list below that apply to the code. A. The add instruction will not execute B. The program will not exit cleanly C. We did not load the address of the data segment D. This is a useless program 24. (note that I didn't write this question, but feel it's somewhat simple and good for a laught. I did put some editorial comments for your reading pleasure...) For some reason you have been writing assembly for the Russian government (note: that's gotta be a great gig), and you're one multiplication away from ensuring that Garfield the Cat will be the next president of the United States (note: Garfield would certainly be an upgrade from recent presidents / presidential candidates). However, the mighty Vladimir Putin himself has coded this multiply (note: how did Putin ever learn assembly language???), and to alter it would be treason (note: time for a job change). Instead you must recalculate valid ranges for all other code to fit these 4 lines (note: that's a clever way of staying alive...). For what values of K will Vlad's code cooperate? Assume unsigned multiplication and that the code will assemble. (4 pts) MOV BX, 42h MOV AX, K MUL BX MOV Multiplication_Result, AX
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