250,(g)+0=(8)250,(8) According to the reaction given above, 0.3 moles of 502 (g) reacts with 0.5 moles of 02 (g). Accordingly, how many moles of 503 (g) are formed in the reaction at most? Also what is the limiting reagent? Your answer: 0.3 moi 50 ( (3) forms - limiting reagent O2(g 1.0 mol 50 , (5) forms - limiting reagent 50 , (8) 1.0 mol sO, ig forms - limiting reagent O2(g) 0.3mol50, ig forms - limiting reagent SO2(g)