255.255.255.224 1. A company has asked for your assistance to create subnets for their network. They plan to use 200.100.40.0/24 address space. They require you to fulfil their host details as shown in the network below. e) or each subnet, give its Subnet ID, lowest host address, highest host address, and broadcast address in table format as shown below. (20) 11100000 128 +64 + 32 +0+0+0+0+ 0 Magic number = 32 Fa0/0 Fa0/1 Fa0/2 Therefore you will increment each subnet ID on the last osted by 32. Fa0/0 Fa0/10-24TT switcho Fa0/1 / 1941 Router 1941 Routeri Subnet ID address Fap Fao Lowest host Highest host Broadcast address address 200.100.40.1 200.100.40.30 200.100.40.31 200.100.40.33 200.100.40.62 200.100.40.63 200.100.40.65 200.100.40.94 200.100.40.95 200.100.40.9 200.100.40. 126 200.100.40. 127 200.100.40.129 200.100.40.222 200.100.40. 159 200.100.40.161 | 200.100.40. 190 200.100.40. 191 200.100.40.193 200.100.40.222 200.100.40.223 200.100.40.225 200.100.40.254 200.100.40.255 AC-PT POO 16 hosts 3 hosts 200.100.40.0 200.100.40.32 200.100.40.64 200.100.40.96 200.100.40. 128 200.100.40. 160 200.100.40. 192 200.100.40.224 PP-PT PC1 Given these requirements a) Determine number of hosts per subnet. Explain. (6) Subnet/24 11111111.1111111111111111.00000000 5 bits are required to meet the host details. 2^5 - 2 = 32 -2 = 30 hosts per subnet created PART 2-Packet Tracer [64] 1. Consider the network topology given below. Using Packet Tracer, build the topology as shown. Use Part 1 to complete the configuration. (10) (2) b) Total number of subnets. Explain. Subnet/24 11111111.11111111.11111111.000 00000 Link to LAN 1 Link to LAN 2 3 bits are borrowed for subnets, 243 = 8 subnets w Sw c) The prefix mask. 11111111.11111111.11111111.11100000 24 + 3 (borrowed bits from the last octet) = /27 d) Subnet mask. Explain 11111111.11111111.11111111.11100000 (3) PART PC3 11100000 128 +64 + 32 + 0 + 0 + 0 + 0 + 0 = 224 2. Configure the following on the Router a. Give the device a host name of Ri (38) 631 words English (United States)