3. [0/1.42 Points] DETAILS PREVIOUS ANSWERS OSCALC1 6.5.245-246. 8/100 Submissions Used MY NOTES ASK YOUR TEACHER PRACTICE ANOTHE The force of gravity on a mass m is F = -((GMm)/x-) newtons. For a rocket of mass m = 1,000 kg, compute the work (in ]) to lift the rocket from x = 6,400 to x = 6,500 km. (Note: G = 6 x 10 1/ N km-/kg and M = 6 x 1024 kg. If you enter your answer in scientific notation, round the decimal value to two decimal places. Use equivalent rounding if you do not enter your answer in scientific notation.) -865.38*106 X Find the work (in ]) to lift the rocket from x = 6,400 km to x -+ co. -56250*1064. [0.48/1.42 Points] DETAILS PREVIOUS ANSWERS OSCALC1 6.5.240-242. 7/100 Submissions Used Find the work (in ft-lb) done by winding up a hanging cable of length 100 ft and weight-density 7 Ib/ft. 70000 ft-lb X How much work (in ft-lb) is done to lift the cable 50 ft? 17500 ft-lb X How much additional work (in ft-lb) is done when winding up the cable of length 100 ft by hanging a 200 lb weight at the end of the cable? 20000 ft-lbA steel chain 10 m long lies in a pile on the ground. Assuming the chain has density 3 kg/m, calculate the work required to lift the chain vertically until it is fully extended with one end touching the ground. Assume that acceleration due to gravity is g = 9.8 m/s 2940 x J (123) Tutorial Recall that work equals force times distance, and recall force is mass times gravity (9.8 -). Consider dividing the chain into segments of width Ay. What is the mass (weight) of one segment of the chain? How is integration used to find the total work done againT. [034\".48 Points] DETAILS PREVIOUS ANSWERS OSCALC1 6.5.247. 2H 00 Submissions Used A rectangular dam is 40 Ft high and 60 ft wide. (a) Compute the total force F (in lb) on the face of the dam when the surface of the water is at the top of the dam. Use the fact that the weightdensity of water is 62.4lb1'ft3. F= 2995200 lb J (b) Compute the total force F (in lb) on the face of the dam when the surface of the water is halfway:r down the dam. F = 2246400 lb X