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3 + 3^2 + 3^3 + ... + 3^n = [3^(n+1) - 3]/2 Use Mathematical induction to establish a formula for n >= 1

3 + 3^2 + 3^3 + ... + 3^n = [3^(n+1) - 3]/2

Use Mathematical induction to establish a formula for n >= 1

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