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3. (8 points) The following code fragment is a 2-process solution to the critical section problem. try[1] true; = le (incs[j]) no-op; while (turn-j and
3. (8 points) The following code fragment is a 2-process "solution" to the critical section problem. try[1] true; = le (incs[j]) no-op; while (turn-j and try[j]) no-op; incs[1] = true; critical section try[i]false; incs[i] -false; turn = j; Does the above "solution" have mutual exclusion? Please explain your
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