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3. A car is timed between three successive points X, Y and Z where XY = YZ = 2 km. It takes 100 s
3. A car is timed between three successive points X, Y and Z where XY = YZ = 2 km. It takes 100 s to travel from X to Y and 150 s to travel from Y to Z. Given that the deceleration of the car is constant, calculate the magnitude of this deceleration. Find also how far the car travels beyond Z before it comes to rest. [Ans: ms2, 816 m.] 75
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