3. a. Use the trendline from your results to predict the concentration of an aqueous KMnO solution that would have an absorbance of 0.450, showing all of your calculations. b. Calculate the volume of a 3.50 x 10' M stock solution of KMnO4 that would be needed to prepare 250.0 mL of this solution. C. Describe how you would physically prepare this solution. fort te wine off fingernrints from the surface of the unknown cample vial before Scatter 0.0000 0.0000 Sample Conc Trans Absorb LnAbsorb Blank 0.0000 100.0000 0.000000 0.0000 Known #1 3.500e-005 78.3538 0.105940 -2.2449 Known #2 7.000e-005 57.3137 0.241742 -1.4199 Known #3 1.050e-004 40.2650 0.395072 -0.9287 Known #4 1.400e-004 30.8413 0.510867 -0.6716 Known #5 1.750e-004 22.2921 0.651848 -0.4279 Unknown 8.9092-005 47.9497 0.319215 -1.1419 1/Absorb 0.0000 9.4393 4.1366 2.5312 1.9575 1.5341 Backscatter 0.0000 0.0010 0.0010 0.0010 0.0010 0.0000 0.0000 0.0000 0.0000 0.0000 0.0010 0.0010 3.1327 Concentration Graph 0.68 0.63 0.58 0.53 0.48 0.43 -- 0.38 0.33 0.28 0.23 0.18 Absorbance 0.13 0.08 0.03 -0.02 -0.07 0 1e-5 2e-5 3e-5 4e-5 5e-5 6e- 57e-5 8e-5 9e-5 0 000105 0.00012 0.000135 0,00015 0.000165 0.00018 Concentration Wavelength: 502 Curve Fit: Y = AX + B Formula: y = 3888.40245x -0.02719 Correlation Coefficient 0.9993