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3. Circle the compound(s) that will be completely deprotonated by NaOCH2 (in other words, reaction with NaOCH3 will lie >99% to the right). H2ONH3

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3. Circle the compound(s) that will be completely deprotonated by NaOCH2 (in other words, reaction with NaOCH3 will lie >99% to the right). H2ONH3

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