Question
3. Hypothesis testing with sample means (small samples) Most engaged couples expect or at least hope they will have high levels of marital longevity. However,
3. Hypothesis testing with sample means (small samples)
Most engaged couples expect or at least hope they will have high levels of marital longevity. However, because 54% of first marriages end in divorce, social scientists have begun investigating influences on marital longevity. (Data source: These data were obtained from the National Center for Health Statistics.)
Suppose a social psychologist sets out to study the role of age of marriage in marital longevity. She measures marital longevity in a random sample of couples married after age 30 and in a random sample of couples married before age 30 and compares the data. Assume that marital longevity is normally distributed and that the variance in longevity is approximately the same among couples married after age 30 as among couples married before age 30.
Step 1: Do the data meet the test requirements?
A. Is there independent random sampling?
No
Yes
B. What is the level of measurement of the variables?
Nominal
Interval-ratio
Ordinal
C. Is the sampling distribution normally distributed?
Yes
No
Step 2: State the null hypothesis.
The social psychologist thinks that couples married after age 30 will have greater relationship longevity than couples married before age 30. Identify the null and research hypotheses:
H0 |
: | |
H1 |
: |
This is a -tailed test.
Step 3: Select the sampling distribution and establish the critical region.
The social psychologist collects data from one sample of couples married after age 30 and another of couples married before age 30. With small samples, the t distribution is used to establish the critical region because the combined less than 100.
Marital Longevity
Couples Married after Age 30 | Couples Married before Age 30 |
---|---|
X1 |
= 29.3 years | X2 |
= 25.6 years |
s1 |
= 9 years | s2 |
= 8 years |
N1 |
= 51 | N2 |
= 54 |
Use the t distribution table that follows to find the critical t-score, the value for a t-score that separates the tail from the main body of the distribution, forming the critical region. To use the table, you will first need to calculate the degrees of freedom (df). The degrees of freedom are . With = 0.01, the critical t-score is .
df | Proportion in One Tail | 0.25 | 0.10 | 0.05 | 0.025 | 0.01 | 0.005 |
---|---|---|---|---|---|---|---|
Proportion in Two Tails | 0.50 | 0.20 | 0.10 | 0.05 | 0.02 | 0.01 | |
1 | 1.000 | 3.078 | 6.314 | 12.706 | 31.821 | 63.657 | |
2 | 0.816 | 1.886 | 2.920 | 4.303 | 6.965 | 9.925 | |
3 | 0.765 | 1.638 | 2.353 | 3.182 | 4.541 | 5.841 | |
4 | 0.741 | 1.533 | 2.132 | 2.776 | 3.747 | 4.604 | |
5 | 0.727 | 1.476 | 2.015 | 2.571 | 3.365 | 4.032 | |
6 | 0.718 | 1.440 | 1.943 | 2.447 | 3.143 | 3.707 | |
7 | 0.711 | 1.415 | 1.895 | 2.365 | 2.998 | 3.499 | |
8 | 0.706 | 1.397 | 1.860 | 2.306 | 2.896 | 3.355 | |
9 | 0.703 | 1.383 | 1.833 | 2.262 | 2.821 | 3.250 | |
10 | 0.700 | 1.372 | 1.812 | 2.228 | 2.764 | 3.169 | |
11 | 0.697 | 1.363 | 1.796 | 2.201 | 2.718 | 3.106 | |
12 | 0.695 | 1.356 | 1.782 | 2.179 | 2.681 | 3.055 | |
13 | 0.694 | 1.350 | 1.771 | 2.160 | 2.650 | 3.012 | |
14 | 0.692 | 1.345 | 1.761 | 2.145 | 2.624 | 2.977 | |
15 | 0.691 | 1.341 | 1.753 | 2.131 | 2.602 | 2.947 | |
16 | 0.690 | 1.337 | 1.746 | 2.120 | 2.583 | 2.921 | |
17 | 0.689 | 1.333 | 1.740 | 2.110 | 2.567 | 2.898 | |
18 | 0.688 | 1.330 | 1.734 | 2.101 | 2.552 | 2.878 | |
19 | 0.688 | 1.328 | 1.729 | 2.093 | 2.539 | 2.861 | |
20 | 0.687 | 1.325 | 1.725 | 2.086 | 2.528 | 2.845 | |
21 | 0.686 | 1.323 | 1.721 | 2.080 | 2.518 | 2.831 | |
22 | 0.686 | 1.321 | 1.717 | 2.074 | 2.508 | 2.819 | |
23 | 0.685 | 1.319 | 1.714 | 2.069 | 2.500 | 2.807 | |
24 | 0.685 | 1.318 | 1.711 | 2.064 | 2.492 | 2.797 | |
25 | 0.684 | 1.316 | 1.708 | 2.060 | 2.485 | 2.787 | |
26 | 0.684 | 1.315 | 1.706 | 2.056 | 2.479 | 2.779 | |
27 | 0.684 | 1.314 | 1.703 | 2.052 | 2.473 | 2.771 | |
28 | 0.683 | 1.313 | 1.701 | 2.048 | 2.467 | 2.763 | |
29 | 0.683 | 1.311 | 1.699 | 2.045 | 2.462 | 2.756 | |
30 | 0.683 | 1.310 | 1.697 | 2.042 | 2.457 | 2.750 | |
40 | 0.681 | 1.303 | 1.684 | 2.021 | 2.423 | 2.704 | |
60 | 0.679 | 1.296 | 1.671 | 2.000 | 2.390 | 2.660 | |
120 | 0.677 | 1.289 | 1.658 | 1.980 | 2.358 | 2.617 | |
0.674 | 1.282 | 1.645 | 1.960 | 2.326 | 2.576 |
Step 4: Computing the test statistic.
To calculate the t statistic, you first need to estimate the population variance. You can estimate the population variance by calculating a weighted sample variance (s(XX)
). The pooled estimate of the standard deviation is . The value of the test statistic is t = . (Hint:For the most precise results, retain four decimal places from your previous calculation to calculate the t statistic.)
Step 5: Making a decision and interpreting the results of the test.
The t statistic in the critical region for this hypothesis test. Therefore, the social psychologist the null hypothesis. The social psychologist conclude that relationships are longer for couples married after age 30 than for couples married before age 30.
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