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3 L 6 ( c ) Derive l n ( L ( t ) L 0 ) = - k t for a BOD test.

3L6(c) Derive ln(L(t)L0)=-kt for a BOD test. Start your answer by defining L(t)=BODL-BOD(t). Assume first-order decay of L during the BOD test (i.e.,dLdt=-kL).
(d) BOD test results are given below, plot -ln(L(t)L0) vs. time. You will have to guess a value for BOD BLAs??eBOBDL is choose "Add Trendline," check for "Linear," set "0" for "Set Interception," and check for "Display equation" and "Display R-square value.") Show the resulting plot in your answer. Once k is found, calculate BODL and compare it with the initial guess.
\table[[Incubation time (days),0,1,2,3,4,5],[Measured BOD ({:mgO2L),0,66,109,147,180,208]]
(e) If the initial guess of BODL(334mgL) were not given, write a short discussion on how you would find BODL.
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