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3. Luis was hired to make some jewelry for a special occasion. He needs to make the jewelry out of an alloy that is 54:

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3. Luis was hired to make some jewelry for a special occasion. He needs to make the jewelry out of an alloy that is 54: silver and he requires 10 ounces. He has a large amount of 45% silver and also some that is 75% silver. How many ounces of the 45: silver and 75% silver does he need? Quantity . Percent = Amount of Let X represent the amount of 45% silver. Let Y represent the amount of 75% silver. Complete the chart below using information from the problem. Mixture problem Quantity Percent (: as PURE silver ounces) decimal) totals 15% alloy X 75% alloy 0. 75 Totals for the 54% mixture This information 0. 54 (10) must be given Use the formula to work across and complete any empty spaces in the last column: Again use the chart's information to fill in the boxes below and set up the system of equations: Amount of 45% Amount of 75% Total amount of 54% silver silver silver Pure silver in Pure silver in Total amount of 45% 75% PURE silver

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