(3 points) Consider a population of 5 literature students. Each student was assigned a final paper assignment. For each student (S, for student 1, S2 for student 2, etc.), the number of pages the student wrote for his or her paper is listed below: S1 = 22, $2 = 77, S3 = 61, S4 = 70, Ss = 52 This is a multi-step problem. Part 1: Find the mean of the population. Round to 4 decimal places if necessary. Answer: Part 2: Part 3: Part 4: Part 5: Part 6: Part 7: Part 8:(2 points) A random sample of 100 observations from a population with standard deviation 25.04 yielded a sample mean of 94.4. Part 1: Given that the null hypothesis is / = 90 and the alternative hypothesis is M > 90 using a = .05, find the following: (a) Test statistic = 1.76 (b) P-value: 0.0392 Note: Round off the test statistic to 2 decimal places and the P-value to 4 decimal places. Part 2: Based on part 1, the conclusion for this test is: A. Reject the null hypothesis O B. There is insufficient evidence to reject the null hypothesis O C. None of the above Part 3: Given that the null hypothesis is / = 90 and the alternative hypothesis is u # 90 using a = .05, find the following: (a) Test statistic = (b) P-value: Note: Round off the test statistic to 2 decimal places and the P-value to 4 decimal places. Part 4:(2 points) Use the following information for all parts of this problem. On a particular golf course, a sample of 38 golfers have a mean golf score of 85. Suppose the population standard deviation for this course is 4.45. Part 1: Using the formula a 90% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter vx where x is any number, type sqrt(x). For example, v2 should be typed as sqrt(2). to Part 2: Part 3: Part 4: Part 5: Part 6: Preview My