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3. Process P1 P2 P3 P4 PS Burst Time 10 1 2 1 S Priority 3 1 3 4 2 Processes arrives in order of

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3. Process P1 P2 P3 P4 PS Burst Time 10 1 2 1 S Priority 3 1 3 4 2 Processes arrives in order of P1, P2, P3, P4 and PS at the same time of O(zero). For FCFS, SJF and non-preemptive priority algorithm a) Find the waiting times for each process. b) Find the average waiting times. c) Draw the Gantt charts

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