3. "R is in neither BCNF nor 3NF." Give evidence to justify your answer. Hint: Start by finding the two candidate keys of R. FOR QUESTION 6, CONSIDER THE FOLLOWING RELATION AND SET OF FUNCTIONAL DEPENDENCIES: R(A, B, C, D, E) FLC B D-A, B, C E A, D . 6. The relation R has only one candidate key, (E, so R is not in BCNF. Decompose it into a set of relations in BCNF that has the lossless join property