3. Two masses sit at the top of two inclined planes that have different angles, as shown in the figure. The height above the bottom of the planes is 3.5 m. Mass Mi = 2.0 kg and mass M2 = 3.0 kg. P 3.5 a. What is the change in potential energy of Mi if it rolls without slipping all the way down the left inclined plane ? 01/ 2 / my 2 ++ 1 18 (2 /5mrz ) mah Ctheexpertta.com b. What is the velocity of Mi when it arrives at the bottom of the left plane? 60 =1 / 2 m v 2 + 1 / 2 0 2 / 5mrz ) W2 4 0 = 1/2 mv2 -+ 1/2 ( 215 m ver/ c. What is the change in potential energy of M2 if it slides without friction all the way down the right plane? 0 = 1/2 mv 2 + 1/ 28 2 1 5 mr 2) V 2 = w 2 d. What is the velocity of M2 when it arrives at the bottom of the right plane? WNC = 1/ 2 mv 2/ 4 1/2 (2/ 8