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3. Use mathematical induction to show that when n is an exact power of 2, the solution of the recurrence n=2. 2k, for k>1 is

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3. Use mathematical induction to show that when n is an exact power of 2, the solution of the recurrence n=2. 2k, for k>1 is T (n) = n Ign. T (n) = 12T (2)

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