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*32. 2. Given the standard free energy of reactions. (1) H2(g)+1/202(g) H20(1) ArGme=-237.2 kJmol-1 (2) CO(g)+1/202(g)--CO2(g) ArGm@=-257.1 kJmol-1 (3) H2O(g)--H20(1) ArGme=-8.6 kJmol-1 (1) Calculate Arme

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*32. 2. Given the standard free energy of reactions. (1) H2(g)+1/202(g) H20(1) ArGme=-237.2 kJmol-1 (2) CO(g)+1/202(g)--CO2(g) ArGm@=-257.1 kJmol-1 (3) H2O(g)--H20(1) ArGme=-8.6 kJmol-1 (1) Calculate Arme for the reaction . CO2(g)+ H2(g) -CO(g)+ H2O(g) AG=EAG (products) -- EAG(reactants) (ii) If at 298.15 K the partial pressures of CO2(g), H2(g), CO(g) H2O(g), are 50.65kPa , 101.3kPa, 202.6kPa, 506.5kPa , respectively, determine the reaction direction by calculation

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