3.22. Two enzymes are immobilized on the same flat, nonporous surface. For enzyme A, the substrate is S1. For enzyme B, the substrate is S2. The product of the first reaction is S2 : S1EAS2EBP Figure 3.P1 depicts the rate of the first reaction on the surface as a function of local concentrations of S1. If the bulk concentration of S1 is 100mg/l and the mass-transfer coefficient is 4105 cm/s, what is the rate of consumption of for a 1cm2 surface? What is the surface concentration of S1? Figure 3P.1. Reaction rate data for problem 3.22. Reaction rate dependence on substrate 1 for reaction catalyzed by EA. b. The rate of the second reaction follows: d[S2]/dt=d[P]/dt=Km+S2surfaceVmS2surface Here Km=5mg/1 (or 5103mg/cm3 ) and Vm=4.0106mg/cm2=s. The bulk concentration of S2[S2bulk] is maintained as 5mg/l, and the mass-transfer coefficient is the same for S1 and S2. Calculate [ S2surface ] and the rate of formation of P (assuming all stoichiometric coefficients are one)