3.A

The rale constant of a chemical reaction increased from 0.100s1t03.10s1 upon raising the Learning Goal: temperature from 250C to 4900C. To use the Adthenius equation to calculate the activation energy. As temperature rises, the avorage kinetic enargy of Part A molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arsthenius equation k=AeL2/RI Calculate the value of (T21T11) where T1 is the initial tempenture and T2 is the final where k is the rate constant, A is the freguency factor, Fa is the activation energy. R=8.3145 J/(K+mol) is the gas oonstant, and T is the Kelvin temperature. The following reartangod versicn of the equation is also useful: ln(k2k1)=(REa)(T11T11) femperature. Express your answer numericallyf where k1 is the rate constant at temperature Tr. and k2 is the rate constant at temperature T2