3s 2s Four small beads are attached to a long string. The first mass is a distance s = 59.9 cm from the free end of the string. The next three masses are attached at distances: 2s, 3s and 4s from the same end of the string. The string is suspended above the ground so that the free end of the string just touches the ground. The string (with beads) is then released so that it falls to the ground. Part 1) Find the times that the first and fourth bead hit the ground: t1= t4 = Part 2) What is the speed of the first and fourth bead as they hit the ground? 21 = m/s V4 = m/s Part 3) Using a new piece of string plus four new beads, place the first bead the same distance s = 59.9 cm from the free end of the string. Now place the remaining three beads at the appropriate distances, $2, $3, and $4 so that the four beads hit the ground at equal time intervals. What are these distances? $2 = cm 83 = cm 84 = cm