4. [0.78/1 Points] DETAILS PREVIOUS ANSWERS SERCP11 3.2.P.014. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER From the window of a building, a ball is tossed from a height y, above the ground with an initial velocity of 8.10 m/s and angle of 23.0 below the horizontal. It strikes the ground 5.00 s later. (a) If the base of the building is taken to be the origin of the coordinates, with upward the positive y-direction, what are the initial coordinates of the ball? (Use the following as necessary: Yo. Assume SI units. Do not substitute numerical values; use variables only.) x = 0 y = 0 (b) With the positive x-direction chosen to be out the window, find the x- and y-components of the initial velocity. 7.45 -3.16 m/s m/s (c) Find the equations for the x- and y-components of the position as functions of time. (Use the following as necessary: y, and t. Assume SI units.) x= 7.45 m X y= X m (d) How far horizontally from the base of the building does the ball strike the ground? 37.25 m (e) Find the height from which the ball was thrown. 138 325 m (f) How long does it take the ball to reach a point 10.0 m below the level of launching? 1.14 S Need Help? Read it Submit Answer