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4. At a substrate concentration of 0.5M, the enzyme in the free state (before enzyme) K m =0.05 mol/L; V max =10.0 mol/L.min. After immobilization

4. At a substrate concentration of 0.5M, the enzyme in the free state (before enzyme) Km=0.05 mol/L; Vmax=10.0 mol/L.min. After immobilization Km= 0.08 mol/L;Vmax= 10.0 mol/Lmin. Calculate the substrate concentration. Rat in the condition that the maximage text in transcribedimage text in transcribed

4. At a substrate concentration of 0.5M, the enzyme in the free state (before enzyme) K=0.05mol/L; Vmax =10.0mol/L.min. After immobilization K was 0.08mol/L;V,10.0 mol/Lmin. Calculate the substrate concentration. Rat in the condition that the max 4. 0.5M () mol/L;Vmax=10.0mol/L.min (15 )

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