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4. Electric Flux Through a Closed Surface A closed triangular box is placed within the the presence of a uniform electric field E = (7.80
4. Electric Flux Through a Closed Surface A closed triangular box is placed within the the presence of a uniform electric field E = (7.80 x 101 - ) ?. Note that this box has five sides, a slanted side, two triangular sides, one that faces the viewer and one on the rear, a rectangular rear side and a a rectangular bottom. Unlike the case of open surfaces, like those in the previous problems, for closed surfaces the area vectors are always defined as pointing outward and away from the closed surface. 30.0 cm y 60 10.0 cm a. A student writes down the area vector for the rear rectangular area of the box as: Arear rect = (300 m?) i. They have made two errors, explain what they are and correct their work. b. Express the area vector of the slanted side of the box, Aslanted, using unit vectors. Explain your expression. c. In order to evaluate the electric flux we can ignore the other three surfaces (i.e. the facing triangular, rear triangular and bottom sides), explain why. d. Calculate the electric flux through the rear rectangular side, rear rect. Explain your work. e. Calculate the electric flux through the slanted side, slanted. Explain your work. f. Find the net flux through the triangular box. In your own words explain what this result means.4. Electric Flux Through a Closed Surface A closed triangular box is placed within the the presence of a uniform electric field E = (7.80 x 101 - ) ?. Note that this box has five sides, a slanted side, two triangular sides, one that faces the viewer and one on the rear, a rectangular rear side and a a rectangular bottom. Unlike the case of open surfaces, like those in the previous problems, for closed surfaces the area vectors are always defined as pointing outward and away from the closed surface. 30.0 cm y 60 10.0 cm a. A student writes down the area vector for the rear rectangular area of the box as: Arear rect = (300 m?) i. They have made two errors, explain what they are and correct their work. b. Express the area vector of the slanted side of the box, Aslanted, using unit vectors. Explain your expression. c. In order to evaluate the electric flux we can ignore the other three surfaces (i.e. the facing triangular, rear triangular and bottom sides), explain why. d. Calculate the electric flux through the rear rectangular side, rear rect. Explain your work. e. Calculate the electric flux through the slanted side, slanted. Explain your work. f. Find the net flux through the triangular box. In your own words explain what this result means
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