4. In a study of attitudes the police, a researcher finds that the average rating of the police on a scale of 1 to 10 being excellent and one being very poor, is 5.40, with a standard deviation of 2.30. Construct confidence intervals for the 95% and 99% confidence levels for each of the following sample sizes: a. 100 b. 250 c. 500 d. 1000 Interpret your results. Mean 5.40 and standard deviation = 2.30 1. Calculate standard error for each of the sample sizes a. Standard error for n= 100 b. Standard error for n=250 C. Standard error for n= 500 d. Standard error for n=1000 2. Find confidence interval using formula for 95% confidence Interval A: CI for n=100 (use 1.96 value and you will get 2 values- below and above the given mean B. CI for n=250 C. CI for n=500 D. CI for n=1000 3. Find confidence interval using formula for 99% confidence interval A: CI for n=100 (use 2.58 value and you will get 2 values- below and above the given mean B. CI for n=250 C. CI for n=500 D. CI for n=1000