4. It is possible to approximate the sum of an infinite series by using the for statement. The following code computes 2 48 16 which converges to 2. (proof). (mathjoke) Here is a code to do the above include #include int main ) int i, n: float sum=0; print f ( "Enter # of terms-"); scanf("td", &n); for (i-0: ic- n i++) sum sum+ 1/pow (2,1) ", sum); rint f("Sum- return 0: %f Write a code to compute the sum (should be close to 1.2) 23 33 43 5 100 Note: pow (a, b) in math.h returns a