4) Let f(x)=ln(x+1) 1. Use the nodes x0=0 and x1=0.6 to find the first Lagrange interpolating polynomial for fx ) (6) px)=0.78334x b) p(x)=0.78334(x0.6) c) p(x)=0.88333x+1 II. Use this polynomial to approximate f(0.45) a) 0.117501 b) 0.602502 (c) 0.352503 111. Find the absolute error = Exact value Approximated value| a) 0.231 6) 0.019 c) 0.489