(4%) Problem 19: A heart pacemaker fires 65 times a minute, each time a 25.0 nF capacitor is charged (by a battery in series with a resistor) to 0.632 of its full voltage. Randomized Variables S = 65 times per minutes Ibekie, Osinigwe - osinigwe.ibekie@doane.edu @theexpertta.com - tracking id: 9N69-E9-85-47-BD7D-37520. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. A What is the value of the resistance in ? d Grade Summary ed R = Deductions ed Potential 100%som. According to the question: ec25. OnF R V = Vosin( t ) Given, A heart pacemaker fires 65 times a minute. tarry the frequency of the pacemaker, f= 65 minute Therefore, the time + = 1 I minute - 60 - 12 get 5 65 13 Now, Voltage on caponitor at time t V=Vol Le */2 ) where I = RC, According to question V = 0. 6 32Y., 0 . 6 3 2 1 = V ( 1 - e - tire ) 2 0 . 632 = 1 - e t/RC - 0 . 368 Taking anatural log both side, we get - The = In ( 0 . 368 ) = - 0 . 90967 - R- t 0 0 99467 C 0. 99967 X25X129 -2 =3. 6935x10-2