(4%) Problem 21: On a one lane road, a person driving a car at v1 = 64 mi/h suddenly notices a truck d = 2.2 mi in front of him. That truck is moving in the same direction at v, = 38 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v, during time interval At. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, V1 assume the direction of motion of the car is the positive direction. Refer to the figure. d Otheexpertta.com A 11% Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax2: traveled by the truck during the time interval At. Ax, = Grade Summary Deductions 0% Potential 100% B At AX, 7 8 9 HOME Submissions a 4 5 6 Attempts remaining: 5 h 1 J 1 2 3 (0% per attempt) detailed view k P + 0 END S t V1 VO BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback A 11% Part (b) Enter an expression for the distance, Ax,: traveled by the car in terms of v1: v, and a. A 11% Part (c) Enter an expression for the acceleration of the car, a, in terms of v1: V2, and At. & 11% Part (d) Enter an expression for Ax, in terms of Ax, and d when the driver just barely avoids collision. A 11% Part (e) Enter an expression for Ax, in terms of v1: V2; and At. A 11% Part (f) Enter an expression for At in terms of d, v1: and v2. & 11% Part (g) Calculate the value of Ar in hours. 4 11% Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2. A 11% Part (i) Calculate the value of a in meters per second squared