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(40%) Problem 1: A kitty cat stands in front of a mirror with radius of curvature 40 cm. While the cat is 30 cm

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(40%) Problem 1: A kitty cat stands in front of a mirror with radius of curvature 40 cm. While the cat is 30 cm tall, its image is only 10 cm tall (and upright). Let's analyze this situation using our equations for curved mirrors. f = || 10% Part (f) Given that the radius of curvature of the mirror is 40 cm, what is f in cm? (Hint: what is the sign of s?) Y () b e g k C d h * ^^45 1 2 3 7 89 6 HOME j n P SB m + - 0 END . VO BACKSPACE DEL CLEAR s' = || 10% Part (h) What is the image distance s'? (in cm) b C d e j g k h m n P SB + Submit () 7 89 ^^45 * - 1 2 0 VO BACKSPACE 6 3. HOME END . DEL CLEAR Hint Feedback I give up!

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