400 kg cylindrical particles of 50% 20 mm size, 40% 40 mm size and 10% 50 mm size will be fluidized using air at 25 C and 2 atm pressure. Under minimum fluidization conditions, the void fraction is 0.50. The bed diameter is 0.5 m and the volume of solid particles is 0.35 m3. For air at 2 atm and 25 C, = 1.845 x 105 Pa s, = 2.374 kg/m3

a) Calculate the minimum height of the fluidized bed b) Calculate the pressure drop at the minimum fluidization condition c) Calculate the minimum velocity for fluidization? d) Calculate the pressure drop per 1m length if the bearing clearance fraction is 0.7 when using 3 times the minimum speed

INTERMEDIATE STEPS AND UNITS MUST BE DETAILED IN THE QUESTION