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A 20-bbl influx of 9.0-lbm/gal salt water enters a 10,000-ft well containing 10-lbm/gal mud. The an- nular capacity is 0.0775 bbl/ft opposite the drillpipe
A 20-bbl influx of 9.0-lbm/gal salt water enters a 10,000-ft well containing 10-lbm/gal mud. The an- nular capacity is 0.0775 bbl/ft opposite the drillpipe and 0.0500 bbl/ft opposite the 600 ft of drill collars. The capacity factor inside the drillpipe is 0.01776 bbl/ft, and the capacity factor inside the drill collars is 0.008 bbl/ft. The formation pressure is 6,000 psia. Assume T=140F. a. Compute the shut-in drillpipe and casing pressure that would be observed after the kick entered the well. Answer: 785 psig; 806 psig. b. Compute the surface annular pressure that would be observed when the top of the saltwater kick reaches the surface if the mud density is in- creased to the kill mud density before circulation of the well. Answer: 208 psig. c. Compute the total pit gain that would be observed when the top of the kick reaches the sur- face. Answer: 20 bbl. d. Compute the surface annular pressure that would be observed if the kick was methane gas in- stead of brine. Answer: 1,040 psig. e. Compute the surface annular pressure that would be observed if the kick was methane gas and the annular capacity was 0.1667 bbl/ft instead of 0.0775 bbl/ft. Assume the gas density is negligible. Answer: 684 psig
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a The shut in drill pipe pressure would be 7 85 ps ig and the shut in casing pressure would be 8 06 ps ig To calculate the shut in drill pipe pressure we need to first calculate the influx volume The ...Get Instant Access to Expert-Tailored Solutions
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